Question

Triangle ABC has coordinates A(2, 1), B(- 1, 0) , and C(3, 4) . What are the coordinates of triangle A'B'C' after the transformation T(3,-1) ( triangle ABC)= triangle A'B'C'?A (5,2), B'(2.1), C'(6,5)A'(5,0). B'(2.-1), C'(6,3)A'(-1.0), B'(-4, -1). C'(0, 3)A'(-1.2). B'(-4.1). C'(0.5)

Answer 1

To make this transformation using the rule T(3, -1), we need to add 3 units in the x-axis to each point, and also subtract one unit to each coordinate in the y-axis. Then, we have:

Point A (2, 1):

A (2, 1), T(3, -1) ---> A' (2+ 3, 1 - 1) =A'(5, 0).

Point B (-1, 0):

B (-1, 0), T(3, -1) ---> B' (-1 + 3, 0 - 1) = B' (2, -1).

Point C (3, 4):

C (3, 4), T(3, -1) ---> C' (3 + 3, 4 - 1) = C' (6, 3).

Then, the coordinates of triangle A'B'C' after the transformation is:

A'(5, 0), B'(2, -1), C' (6, 3).