Using the formula
[tex]A=p(1+\frac{r}{n})^{nt}[/tex]From the question,
P=$1250 r=0.057 t=3 n=2
Substitute the values into the formula and evaluate
[tex]A=1250(1+\frac{0.057}{2})^{2\times3}[/tex][tex]=1250(1+0.0285)^6[/tex][tex]=1250(1.0285)^6[/tex][tex]=\text{ \$1479.57}[/tex]