Question

At gas station, the revenue R varies directly with the number of gallons of gas sold. if the revenue is $51 when the number of gallons sold is 15, find the linear equation that relates revenue R to the number of gallons of gas. then find the revenue when the number of gallons of gas sold is 5.5

Answer 1

Given,

The revenue is directly varies to the number of gallon sold.

The revenue of the gas is $51 when the number of gas sold is 15 gallons.

Required

The revenue amount when the number of gas sold is 5.5 gallons.

According to the question,

$\begin{gathered} Revenuse\propto Number\text{ of gallons sold} \\ R=kN \end{gathered}$

Here, R = revenue, k is proportionality constant and N = number of gallons sold.

Substituting the values then,

$\begin{gathered} R=kN \\ 51=k(15) \\ k=\frac{51}{15} \\ k=\frac{17}{5} \end{gathered}$

The value of k is 17/5.

The linear equation that relates R to number of gallons of gas is:

$R=\frac{17}{5}N$

The amount of revenue at 5.5 gallons of gas sold.

$\begin{gathered} R=\frac{17}{5}\times5.5 \\ =17\times1.1 \\ =18.7 \end{gathered}$

Hence, the revenue amount is $18.7.