Question

A stone is projected at an angle of 60 degree and an initial velocity of 20 ms^(-1). Determine the time of flight:

Answer 1

Given data:

* The angle of projectile with the horizontal axes is,

$\theta=60^{\circ}$

* The initial velocity of the projectile is,

$u=20ms^{-1}$

Solution:

The time of flight of the given projectile is,

$T=\frac{2u\sin (\theta)}{g}$

where g is the acceleration due to gravity, and T is the time of flight,

Substituting the known values,

$\begin{gathered} T=\frac{2\times20\times\sin (60^{\circ^{}})}{9.8} \\ T=3.53\text{ s} \end{gathered}$

Thus, the time of flight for the given projectile is 3.53 seconds.