Question

Find the distance d(p1 p2) between the points p1 and p2. P1 = (2.3,1.3) P2 = (-0.7,1.1)

Answer 1

Answer:

d(p1,p2)=√9.04 units.

Explanation:

The distance between two points is calculated using the formula:

$Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Given the two points:

$\begin{gathered} (x_1,y_1)=P_1(2.3,1.3) \\ \left(x_2,y_2\right)=P_2\left(-0.7,1.1\right) \end{gathered}$

Substitute into the formula given above:

$\begin{gathered} d=\sqrt{(-0.7-2.3)^2+(1.1-1.3)^2} \\ =\sqrt{(-3)^2+(-0.2)^2} \\ =\sqrt{9.04}\text{ units} \end{gathered}$

The distance between points p and p2 is √9.04 units.