We are given a probability of p = 43% = 0.43. we are asked to determine the probability of finding at most 3 out of 6 individuals that believe in reincarnation, that is:
[tex]P(x\le3)[/tex]Since this is a discrete variable we have the following:
[tex]P(x\le3)=P(x=1)+P(x=2)+P(x=3)[/tex]The probability that x = n, being "n" a natural number is:
[tex]P(x=n)=\text{kCn}\times p^k\times(1-p)^{k-n}[/tex]