Question:
Triangle GHI with vertices G(-4,2),H(-2,4), and I(-7,7) drawn in a rectangle. what is the area in square units of triangle GHI .
Solution.
By definition, the area of a triangle is:
[tex]A\text{ = }\frac{b\text{ x h}}{2}[/tex]Now, the area of the triangle GHI is the area of the square minus the triangles that surround the triangle GHI.
The area of the square is:
Area of square =AS= b x h = 5 x 5 = 25
Area of left triangle =
[tex]A_l\text{ = }\frac{b\text{ x h}}{2}\text{ = }\frac{3\text{ x }5}{2}=\text{ }\frac{15}{2}[/tex]Area of the upper right triangle
[tex]A_{sr}\text{ = }\frac{b\text{ x h}}{2}\text{ = }\frac{5\text{ x }3}{2}=\text{ }\frac{15}{2}[/tex]Area of the lower right triangle
[tex]A_{lr}\text{ = }\frac{b\text{ x h}}{2}\text{ = }\frac{2\text{ x }2}{2}=2[/tex]Thus, area A of the triangle GHI is:
[tex]A=AS-(A_l+A_{sr}+A_{lr}\text{)}[/tex]that is:
[tex]A=25-(15+2_{}\text{) = 25-17 = 8}[/tex]Then, we can conclude that the area of the triangle GHI is:
[tex]A=\text{8}[/tex]