Hi, I was absent today in class and I really need help with question 6I will be much appreciated if you show work and the step so I can be more understanding thank you!

Recall that:
[tex]\log _ba=\frac{\ln a}{\ln b}\text{.}[/tex]Therefore:
[tex]\begin{gathered} x=\log _7513=\frac{\ln (513)}{\ln (7)} \\ x\approx\frac{6.24027584}{1.94591014}, \\ x\approx3.207. \end{gathered}[/tex]Answer:
[tex]x\approx3.207.[/tex]