Hi, I was absent today in class and I really need help with question 6I will be much appreciated if you show work and the step so I can be more understanding thank you!

Hi I was absent today in class and I really need help with question 6I will be much appreciated if you show work and the step so I can be more understanding tha class=

Respuesta :

Recall that:

[tex]\log _ba=\frac{\ln a}{\ln b}\text{.}[/tex]

Therefore:

[tex]\begin{gathered} x=\log _7513=\frac{\ln (513)}{\ln (7)} \\ x\approx\frac{6.24027584}{1.94591014}, \\ x\approx3.207. \end{gathered}[/tex]

Answer:

[tex]x\approx3.207.[/tex]

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