Given data
*The given diameter of the Ferris wheel is d = 54 feet
*The given rate is 10 revolutions per hour
(A)
The angular speed of the wheel in radian per hour is calculated as
[tex]\begin{gathered} \omega=2\pi\times10 \\ =20\times3.14 \\ =62.8\text{ radian/h} \end{gathered}[/tex]Hence, the angular speed of the wheel in radian per hour is 62.8 radian/h
(b)
The radius of the wheel is calculated as
[tex]\begin{gathered} r=\frac{d}{2} \\ =\frac{54}{2} \\ =27\text{ } \end{gathered}[/tex]The formula for the linear speed of passengers in feet per hour is calculated as
[tex]v=\omega r[/tex]Substitute the values in the above expression as
[tex]\begin{gathered} v=(62.8)(27) \\ =1695.6 \end{gathered}[/tex]Hence, the linear speed of passengers in feet per hour is 1695.6 feet/hour
