Respuesta :
Answer:
The coordinates of the fourth vertex of the rectangle is (3,-8).
Step-by-step explanation:
It is given that a rectangle has vertices at these coordinates. (1, 2) , (3, 2) , (1, −8).
Let the coordinates of the fourth vertex of the rectangle be (x,y).
The diagonals of rectangle intersect each other at their midpoint.
Plot these points on a coordinate plane. From the graph it is noticed that the end point of one diagonal are (3, 2) and (1, −8).
[tex]Midpoint=(\frac{3+1}{2},\frac{2-8}{2})=(2,-3)[/tex]
The end point of second diagonal are (1, 2) and (x,y).
[tex]Midpoint=(\frac{1+x}{2},\frac{2+y}{2})[/tex]
Since the diagonals of rectangle intersect each other at their midpoint, therefore
[tex](\frac{1+x}{2},\frac{2+y}{2})=(2,-3)[/tex]
On comparing both the sides,
[tex]\frac{1+x}{2}=2\Rightarrow 1+x=4\Rightarrow x=3[/tex]
[tex]\frac{2+y}{2}=-3\Rightarrow 2+y=-6\Rightarrow y=-8[/tex]
Therefore the coordinates of the fourth vertex of the rectangle is (3,-8).
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