I thought the answer was 8square root 5 but that’s not correct. I just need help on how I can solve this problem and the ones after.

We are given the following information:
This is a right triangle with sides:
[tex]a=8,b=?,c=16[/tex]We will obtain the length of ''b'' using the Pythagoras theorem. We have:
[tex]\begin{gathered} c^2=a^2+b^2 \\ c^2-a^2=b^2 \\ b^2=c^2-a^2 \\ \text{Taking the square roots of both sides, we have:} \\ b=\sqrt[]{c^2-a} \\ b=\sqrt[]{16^2-8^2} \\ b=\sqrt[]{256-64} \\ b=\sqrt[]{192} \\ b=\sqrt[]{64\cdot3} \\ b=\sqrt[]{64}\cdot\sqrt[]{3} \\ b=8\sqrt[]{3} \\ \\ \therefore b=8\sqrt[]{3} \end{gathered}[/tex]