The given expression is-
[tex]2x(x^2+5x-4)[/tex]We have to find three solutions for this expression. First, we use the zero property to find the first solution.
[tex]\begin{gathered} 2x(x^2+5x-4)=0 \\ 2x=0 \\ x^2+5x-4=0 \end{gathered}[/tex]Where,
[tex]x_1=0[/tex]Now, we solve the quadratic equation to find the other two solutions.-
[tex]x^2+5x-4=0\rightarrow(x+a)(x-b)=0[/tex]We have to find the two solutions using the quadratic formula-
[tex]x_{1,2}=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}[/tex]Where a=1, b=5, and c=-4.
Using the given information, we have
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