Let x be the number of peanuts pounds and y be the number of almod pounds. Then, we can write
[tex]3x+5.50y=4.50(10)[/tex]and
[tex]x+y=10[/tex]Then, we have 2 equations in 2 unknowns. By multipliying by -3 the secon equation, we have an equivalent system of equations:
[tex]\begin{gathered} 3x+5.50y=45 \\ -3x-3y=-30 \end{gathered}[/tex]so, by adding both equations, we get
[tex]2.5y=15[/tex]which gives
[tex]\begin{gathered} y=\frac{15}{2.5} \\ y=6 \end{gathered}[/tex]Then, by substituting this result into the equation x+y=10, we obtain
[tex]x+6=10[/tex]which gives
[tex]\begin{gathered} x=10-6 \\ x=4 \end{gathered}[/tex]Therefore, she needs 4 pounds of peanuts and 6 pound of almonds