Question

sodium and oxygen react to produce sodium oxide. How many grams of Sodium oxide can be produced from 1.59 moles of sodium

Answer 1

ANSWER

The amount of sodium oxide to be produced is 49.23 grams

EXPLANATION

Given that;

The number of moles of sodium is 1.59 moles

Follow the steps below to find the mass of sodium oxide produced

Step 1; Write a balanced equation for the reaction

$\text{ 4 Na}_{(s)}\text{ + O}_{2(g)}\rightarrow\text{ 2Na}_2O$

In the above chemical equation, 4 moles Na react with 1 mole O2 to give 2 moles Na2O

Step 2; Find the moles of Na2O using a stoichiometry ratio

Let x represents the moles of sodium oxide

$\begin{gathered} \text{ 4 mole Na }\rightarrow\text{ 2 moles Na}_2O \\ \text{ 1.59 mles Na }\rightarrow\text{ x mole Na}_2O \\ \text{ cross multiply} \\ \text{ x mole Na}_2O\text{ }\times\text{ 4 mole Na = 2 moles Na}_2O\times\text{ 1.59 moles Na} \\ \text{ Isolate x} \\ \text{ x = }\frac{2\text{ }\times\text{ 1.59}}{4} \\ x\text{ = }\frac{3.18}{4} \\ \text{ x = 0.795 mol} \end{gathered}$

The number of moles of sodium oxide is 0.795 mol

Step 3; Find the grams of sodium oxide using the formula below

$\begin{gathered} \text{ mole = }\frac{\text{ mass }}{\text{ molar mass}} \\ \text{ cross multiply} \\ \text{ mass = mole }\times\text{ mass number} \end{gathered}$

Recall, that the molar mass of Na2O is 61.9789 g/mol

$\begin{gathered} \text{ mass = 0.795 }\times\text{ 61.9789} \\ \text{ mass = 49.23 grams} \end{gathered}$

Therefore, the amount of sodium oxide to be produced is 49.23 grams