Question

How much work in joules is done when the piston expands from a volume of 13.27 Liters to 76.55 Liters against a pressure of 14.89 atm?

Answer 1

Answer:

The work is -95445 J.

Explanation:

First, let's see the formula of work:

$W=-P\Delta V.$

Where W is work, P is pressure, and ΔV is the change of volume (ΔV = Final volume - Initial volume).

As we have the given data, we can replace what we have in the formula, like this:

$\begin{gathered} W=-14.89\text{ atm}\cdot(76.55-13.27)\text{ L}, \\ W=-942.2\text{ }atm\cdot L. \end{gathered}$

But remember that the answer must be in joules (J). Remember that 1 atm-L equals 101.3 J:

$-942.2\text{ }atm\cdot L\cdot\frac{101.3\text{ J}}{1\text{ atm}\cdot L}=-95444.86\text{ J.}$

The answer would be that the work is -95445 J.