Question

g(a)=-4a +4h(a)=-2a²-4find (g-h) (8)

Answer 1

Given:

$\begin{gathered} g(a)=-4a+4 \\ h(a)=-2a^2-4 \end{gathered}$$(g-h)(8)\text{ is}$

Firstly (g-h)(a) is:

$\begin{gathered} g(a)=-4a+4 \\ h(a)=-2a^2-4 \\ (g-h)(a)=-4a+4-(-2a^2-4) \\ (g-h)(a)=-4a+4+2a^2+4 \\ (g-h)(a)=2a^2-4a+8 \end{gathered}$

At a=8.

$\begin{gathered} (g-h)(a)=2a^2-4a+8 \\ (g-h)(8)=2(8)^2-4(8)+8 \\ (g-h)(8)=(2\times64)-32+8_{} \\ (g-h)(8)=128-32+8 \\ (g-h)(8)=104 \end{gathered}$