Question

some instruments differentiate individual quanta of electromagnetic radiation based on their energies. Assume search and instrument has been adjusted to detect photons that have 1.00 x 10^-16 J of energy. What is the wavelength of the detected radiation? Give your answer in nanometers and in meters.

Answer 1

Answer:

1.9902 nano meter is the wavelength of the detected radiation.

Explanation:

$E=\frac{hc}{\lambda}$

$\lambda$ = Wavelength of radiation

E= energy of the photon of the wave

h = Planck's constant = $6.634\times 10^{-34}Js$

c = speed of light = $3\times 10^8m/s$

$\lambda = \frac{hc}{E}$

Energy of the radiations = E = $1.00\times 10^{-16} J$

$=\frac{6.634\times 10^{-34}Js\times 3\times 10^8 m/s}{1.00\times 10^{-16} J}$

$\lambda =19.902\times 10^{-10}m=1.9902 nm$

$1 m = 10^9 nm$