This is the answer… but how do I SHOW it?

Given:
[tex]y=-3x^2[/tex]We need to find points that line on the given equation to draw the graph.
Set x=-2 and substitute in the equation to find the value of y.
[tex]y=-3(-2)^2[/tex][tex]y=-3\times4[/tex][tex]y=-12[/tex]We get the point (-2,-12).
Set x=-1 and substitute in the equation to find the value of y.
[tex]y=-3(-1)^2=-3[/tex]We get the point (-1,-3).
Set x=0 and substitute in the equation to find the value of y.
[tex]y=-3(0)^2=0[/tex]We get the point (0,0).
Set x=1 and substitute in the equation to find the value of y.
[tex]y=-3(1)^2=-3[/tex]We get the point (1,-3)
Set x=2 and substitute in the equation to find the value of y.
[tex]y=-3(2)^2=-12[/tex]We get the point (2,-12).
Mark the points (-2,-12), (-1, -3), (0,0), (1,-3) and (2,-12) on th egraph and join all the point by curve.
The graph is