Question

what is the length of a non-face diagonal of a 4-in. cube?

Answer 1

Answer:

The length of the diagonal is

$4\sqrt[]{2}\text{ in}$

Explanation:

The length of the diagonal, d can be obtained by applying the Pythagorean Theorem.

$\begin{gathered} d^2=4^2+4^2 \\ =2(4^2) \\ d=4\sqrt[]{2} \end{gathered}$