Two events are happening in this problem. Let's take a look first at the probability of getting a jack in a standard 52 card deck. There are 4 jacks present in the 52 card deck, hence, the probability of getting jack is
[tex]P(jack)=\frac{4}{52}=\frac{1}{13}[/tex]After one jack was drawn, there are 51 cards remaining in the deck. There are 4 ten cards present in the deck, hence, the probability for this will be
[tex]P(ten)=\frac{4}{51}[/tex]To get the overall probability of getting a jack on the first draw and ten on the second draw, just multiply the probabilities above. We get
[tex]P=\frac{1}{13}\cdot\frac{4}{51}=\frac{4}{663}[/tex]The answer to this problem is 4/663.