Substitute x=1 in the above expression.
[tex]\begin{gathered} \sqrt[]{\frac{27\times1^5}{21}}=\sqrt[]{\frac{27\times1}{21}} \\ =\sqrt[]{\frac{27}{21}} \\ =\sqrt[]{\frac{9}{7}} \\ \approx1.134 \end{gathered}[/tex]Given:
[tex]3x^2\sqrt[]{\frac{x}{7}}[/tex]Substitute x=1 in the above expression.
[tex]\begin{gathered} 3\times1^2\times\sqrt[]{\frac{1}{7}}=3\times1\times\sqrt[]{\frac{1}{7}} \\ =3\times\sqrt[]{\frac{1}{7}} \\ \approx3\times0.378 \\ \approx1.134 \end{gathered}[/tex]The value of both the expression are aproximately equals to 1.134 .Thus, the corect option is the first one, 'The value of x=1 yeild approximately 1.134 for each expression, so the '