Respuesta :

11) We have the vertices F(-2,2), G(-2,-4) and H(-4,-4).

We have to apply a dilation with center at (0,0) and a factor of dilation of k = 3.

A dilation with center at (0,0) has the following rule:

[tex](x,y)\to(kx,ky)=(3x,3y)[/tex]

Then, we can apply this rule to the three vertices as:

[tex]\begin{gathered} F=(-2,2)\to F^{\prime}=(3(-2),3(2))=(-6,6) \\ G=(-2,-4)\to G^{\prime}=(3(-2),3(-4))=(-6,-12) \\ H=(-4,-4)\to H^{\prime}=(3(-4),3(-4))=(-12,-12) \end{gathered}[/tex]

We can then graph the pre-image and the image as:

Ver imagen FaizanC236118
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