Question

write the equation of the line that passes through the following points: (3,6) (6,7)

Answer 1

The equation of the lien that passes through two coordinates:

$y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)_{}$

Given coordinates : (3,6) (6,7)

$(x_1,y_1)=(3,6)(x_2,y_2)=(6,7)$

Substitute the values and simplify:

$\begin{gathered} y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)_{} \\ y-6=\frac{7-6}{6-3}(x-3) \\ y-6=\frac{1}{3}(x-3) \\ 3(y-6)=(x-3) \\ 3y-18=x-3 \\ x-3y-3+18=0 \\ x-3y+15=0 \end{gathered}$

The equation of the line that passes through the following points: (3,6) (6,7)​ is x - 3y + 15 = 0

Answer: x - 3y + 15 = 0