The given expression can be rewritten as;
[tex]x^2(2x+1)\text{ -}(2x+1)[/tex]If we expand the above equation, we'll still have the same expression in the question.
We can now factorize, which will give us;
[tex](x^2-1)(2x+1)[/tex]We apply the difference of two squares , we'll then have;
[tex]x^2-1\text{ = }(x^2-1^2)=\text{ }(x-1)(x+1)[/tex]So, we'll then have the below as factors;
[tex](x-1)(x+1)(2x+1)[/tex]The roots of the polynomial then will be 1, -1, -1/2 which we'll get from equating each factor to zero and solving for x.