Respuesta :

The point B has coordinates (-4,2) and C has coordinates (-2,-2). We are going to calculate the slope of the line

[tex]m=\frac{y2-y1}{x2-x1}=\frac{-2-2}{-2-(-4)}=-2[/tex]

Then, we are going to calculate the intercept using the slope m=-2 and the point (-4,2).

y=mx+b

2 = -2*(-4)+b

Isolating b we get

2-8=b= -6

The equation would be

y=-2x-6, option A

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