Question

A health instructor surveyed all her students, and tallied the results. The first survey question asked, "Do you adhere to a vegetarian diet or omnivorous diet?" The second question asked, "If you were to buy a pet today, which animal would it be?" Dog Cat Lizard 5 4 A vegetarian diet An omnivorous diet 5 4 What is the probability that a randomly selected student adheres to an omnivorous diet and would buy a dog? Simplify any fractions

Answer 1

$\begin{gathered} P(A\cap B)=\text{ Probability that a randomly selected student adheres to an} \\ \text{omnivoruos diet and would by a dog} \\ From\text{ the given information there are }4\text{ students who adhere to an} \\ \text{omnivoruos diet and would by a dog} \\ \text{Also }there\text{ are 27 students who answered the survey} \\ P(A\cap B)=\text{ }\frac{4}{27} \\ \\ \text{The Probability that a randomly selected student adheres to an} \\ \text{omnivoruos diet and would by a dog is }\frac{4}{27} \end{gathered}$