pH = 2.6
pOH = 11.4
The formula for calculating the pH of a solution is given as;
[tex]pH=-log[H^+][/tex]Given the following parameter
[tex][H^+]=2.5\times10^{-3}[/tex]Substitute the given parameter into the formula
[tex]\begin{gathered} pH=-log(2.5\times10^{-3}) \\ pH=-log(0.0025) \\ pH=-(-2.6) \\ pH=2.6 \end{gathered}[/tex]Determine the pOH of the solution
[tex]\begin{gathered} pH+pOH=14 \\ pOH=14-pH \\ pOH=14-2.6 \\ pOH=11.4 \end{gathered}[/tex]Therefore the pH and pOH of the solutionare 2.6 and 11.4 respectively