Question

Now, find the equation of the tangent line to the curve at (1, 4). Write your answer in

Answer 1

Given the following question:

$(5-3x)^2$

Find the derivative:

$\begin{gathered} (5-3x)^2 \\ \frac{d}{dx}\mleft(\mleft(5-3x\mright)^2\mright) \\ (5-3x)^2=2\mleft(5-3x\mright)\frac{d}{dx}\mleft(5-3x\mright) \\ 2\mleft(5-3x\mright)\frac{d}{dx}\mleft(5-3x\mright) \\ (5-3x)=-3 \\ 2\mleft(5-3x\mright)\mleft(-3\mright) \\ 2\times-3=-6 \\ -6\mleft(5-3x\mright) \\ =-6\mleft(5-3x\mright) \end{gathered}$

The derivative is -6(5-3x) (I'm only able to answer one question per session)