we know that
Each year, its value is 80% of its value the year before
that is the same as
Each year the value decreases by 20%
we have an exponential decay function of the form
[tex]y=a(1-r)^x[/tex]where
y is the value of the computer laptop
x is the number of years
r is the rate
a is the initial value
so
we have
a=$3,200
r=20%=20/100=0.20
substitute
[tex]\begin{gathered} y=3,200(1-0.20)^x \\ y=3,200(0.80)^x \end{gathered}[/tex]For y=$700
substitute in the equation above
[tex]\begin{gathered} 700=3,200(0.80)^x \\ solve\text{ for x} \\ \frac{700}{3,200}=(0.80)^x \end{gathered}[/tex]Apply log on both sides
[tex]\begin{gathered} log(\frac{700}{3,200})=x*log(0.80) \\ x=6.81\text{ years} \end{gathered}[/tex]therefore