Question

Compute the value of the discriminant and give the number of real solutions of the quadratic equation.-2x² + 6x - 3=0Discriminant:12Number of real solutions:

Answer 1

The formula for the value of discriminant in a quadratic equation in the form ax^2 + bx + c = 0 is :

$d=b^2-4ac$

Where d is the discriminant and

a, b, c are the coefficients in the quadratic equation.

From the given problem,

$ax^2+bx+c=0\Rightarrow-2x^2+6x-3=0^{}$

a = -2, b = 6 and c = -3

Using the formula above,

$\begin{gathered} d=b^2-4ac \\ d=6^2-4(-2)(-3) \\ d=36-24 \\ d=12 \end{gathered}$

Note that if the discriminant is greater than 0, the number of real solution is 2.

The answer is

discriminant = 12

Number of real solutions = 2