Question

g(n) = 3n - 4f(n) = n^3 - 2nFind (gºf)(n)

Answer 1

hello

let's get the functions out first

$g(n)=3n-4$$f(n)=n^3-2n$$g\cdot f(n)=\text{ ?}$$\begin{gathered} g.f(n)=(3n-4)\cdot(n^3-2n) \\ g\mathrm{}f(n)=3n^4-6n^2-4n^3+8n \\ g\mathrm{}f(n)=3n^4-4n^3-6n^2+8n \end{gathered}$