Question

The equation below describes a circle. What are the coordinates of the centerof the circle?(x-4)^2 + (y+12)^2 = 17²O A. (4,12)OB. (-4,-12)O C. (-4,12)OD. (4, -12)21

Answer 1

Solution:

The equation is given below as

$(x-4)^2+(y+12)^2=17^2$

Concept:

The general equation of a circle is given below as

$\begin{gathered} (x-h)^2+(y-k)^2=r^2 \\ where, \\ (h,k)=center \end{gathered}$

Hence,

By comparing coefficients, we will have the center of the circle be

$(h,k)\Rightarrow(4,-12)$

Hence,

The final answer is

$\Rightarrow(4,-12)$

OPTION D is the right answer