Hi, can you help me to solve this problem, please!!!

Given:
The equation of a parabola is given as,
[tex]y=x^2-5[/tex]The objective is to find the axis of symmetry of the parabola.
Explanation:
The general formula to find the axis of symmetry of a parabolic equation is,
[tex]x=-\frac{b}{2a}\text{ .. . . . . (1)}[/tex]From the given equation,
[tex]\begin{gathered} a=1 \\ b=0 \\ c=-5 \end{gathered}[/tex]On plugging the obtained values in equation (1),
[tex]\begin{gathered} x=-\frac{0}{2(1)} \\ x=0 \end{gathered}[/tex]Hence, the axis of symmetry of the parabola is at x = 0.