Given:
The total number digits =8
The number of digits in the pin =4
The number of four-digit pin=
[tex]8C_4=\frac{8!}{4!(8-4)!}[/tex][tex]=\frac{8!}{4!\times4!}=\frac{8\times7\times6\times5\times4!}{4\times3\times2\times4!}=2\times7\times5=70[/tex]There is 70 possible four-digit pin.