Use z scores to compare the given values. The tallest living man at one time had a height of 233 cm. The shortest living man at that time had a height of 74.5 cm. Heights of men at that time had a mean of 176.75 cm and a standard deviation of 6.24 cm. Which of these two men had the height that was more extreme?

Use z scores to compare the given values The tallest living man at one time had a height of 233 cm The shortest living man at that time had a height of 745 cm H class=

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Given:

The tallest living man at one time had a height of 233 cm. The shortest living man at that time had a height of 74.5 cm. Heights of men at that time had a mean of 176.75 cm and a standard deviation of 6.24 cm.

Required:

We need to find that which man had the height that was more​ extreme

Explanation:

The formula for z-score is

[tex]z-score=\frac{X-\mu}{\sigma}[/tex]

where

[tex]\begin{gathered} X\text{ is hirght} \\ \mu\text{ is mean} \\ \sigma\text{ is standard deviation} \end{gathered}[/tex]

put the values for tallest

[tex]z=\frac{233-176.75}{6.24}=9.01[/tex]

now for shortest

[tex]x=\frac{74.5-176.75}{6.24}=-16.39[/tex]

more the z-score more will be the extreme.

Final answer:

z-score for talles is 9.01

z-score for shortest is -16.39

and the extreme is tallest men

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