Question

In order to solve 6x^2+ 4x – 3 = 0 by the quadratic formula, useA = ?B= ?C= ?

Answer 1

To solve the quadratic formula, we use the next form:

$ax^2+bx+c$

Now, we have the next equation given:

$6x^2+4x-3=0$

Therefore,

a=6

b=4

c=-1

The equation formula is given by the next :

$x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}$

Replacing the variables:

$x=\frac{-(4)\pm\sqrt[]{(4)^2-4(6)(-3)}}{2(6)}$

Solving:

$x=\frac{-4\pm\sqrt[]{16+72}}{12}$$x=\frac{-4\pm\sqrt[]{88}}{12}$