Hello!
We have the equation below:
[tex]-3x^3-18x^2-24x[/tex]First of all, note that in all terms we have multiples of -3x. So, let's put it in evidence:
[tex]-3x\cdot(x^2+6x+8)[/tex]Now, let's rewrite 6x as 4x+2x:
[tex]-3x\cdot(x^2+4x+2x+8)[/tex]Note that we can put x in evidence because of the first and second terms, and 2 in evidence because of the third and fourth terms. Look:
[tex]-3x\cdot(x^\cdot(x+4)+2(x+4))[/tex]As we have (x+4) twice, let's put it in evidence too:
[tex]-3x\cdot(x+4)\cdot(x+2)[/tex]Answer:Alternative B. -3x(x+2)(x+4)