Question

What is the quotient of {18x^3 y^3 + 27x^2 y-36xy^2 + 45xy}÷(9xy)?

Answer 1

the equation is:

$\frac{18x^3y^3+27x^2y-36xy^2+45xy}{9xy}$

Now if you realise all the numbers in the numerator are multiples of 9, and also all terms have at least one x and one y, so we can take a common factor:

$\frac{9xy(2x^2y^2+3x-4y+5)}{9xy}$

if you want to prove this, you can use the distribution propertie. and now we can simplify the equation:

$2x^2y^2+3x-4y+5$