We have to solve:
[tex](3\text{ 3/5})\cdot(-8\text{ 1/3})[/tex]We start by converting the mixed number into fractions:
[tex]3\text{ 3/5}=3+\frac{3}{5}=\frac{3\cdot5+3}{5}=\frac{15+3}{5}=\frac{18}{5}[/tex][tex]-8\text{ 1/3}=-8-\frac{1}{3}=\frac{-8\cdot3-1}{3}=\frac{-24-1}{3}=-\frac{25}{3}[/tex]Then, multiply both fractions:
[tex]\frac{18}{5}\cdot(-\frac{25}{3})=-\frac{18}{3}\cdot\frac{25}{5}=-6\cdot5=-30[/tex]Answer: the result of the product is 30.
