Question

-3 times a number is at least 18 solve the inequality above A {n l n <_ -6} B {n l n _> -6}C {n l n <_ -54}D {n l n _> -54}

Answer 1

Explanation:

-3 times a number is (-3n) - if we call the number n.

At least 18 means that it's 18 or more - equal or greater than.

The inequality is:

$-3n\ge18$

To solve we have to divide both sides by -3. This flips the inequality sign, because we're dividing by a negative number:

$\begin{gathered} n\le\frac{18}{-3} \\ n\le-6 \end{gathered}$

Answer:

The solution is n ≤ -6