Step 1
Interprete the range of x
The range is 0
This means that x>0 but x<6
Step 2
Differentiating y with respect to x, we have
[tex]\begin{gathered} \frac{dy}{dx}=5\cos x+3(\sin x(-\sin x)+\cos ^2x) \\ \frac{dy}{dx}=5\cos x+3(\cos ^2x-\sin ^2x)=5\cos x+3\cos 2x \\ \frac{d^2y}{d^2x}=-5\sin x-6\sin 2x \end{gathered}[/tex]Step 3: Find the stationary point,
At the stationary points, we have
[tex]\begin{gathered} 5\cos x+3(\cos ^2x-\sin ^2x)=0 \\ 5\cos x+3(2\cos ^2x-1)=0 \\ 6\cos ^2x+5\cos x-3=0 \end{gathered}[/tex][tex]\text{Let m }=\cos x[/tex]Then,
[tex]\begin{gathered} 6m^2+5m-3=0 \\ m=-1.2374,\text{ or }0.4041 \end{gathered}[/tex]Since the values of cos x cannot be less than -1, then the only possibility is
[tex]\begin{gathered} \cos x=0.4041 \\ x=1.1548 \end{gathered}[/tex]