Start using the distributive
[tex]\frac{8x}{5}-\frac{6}{5}-2x=\frac{4}{5}-x[/tex]bring the constants and variables to contrary sides
[tex]\frac{8}{5}x-2x+x=\frac{4}{5}+\frac{6}{5}[/tex]simplify each side
[tex]\frac{3}{5}x=\frac{10}{5}[/tex]solve for x
[tex]\begin{gathered} 3x=\frac{10\cdot5}{5} \\ x=\frac{10}{3} \end{gathered}[/tex]
