The Solution:
Let the number of True/False questions in the assessment be represented with x.
And the number of multiple-choice questions be represented with y.
Given that the total number of questions is 20.
We have,
[tex]x+y=20\ldots\text{eqn}(1)[/tex]Given that each True/False question is worth 3 points while each multiple-choice question is worth 11 points and the total value of the whole question is 100 points.
We have,
[tex]3x+11y=100\ldots\text{eqn}(2)[/tex]We are required to find the number of the True/False questions (x) and the number of multiple-choice questions (y).
Solving the eqn(1) and eqn(2) simultaneously by the Substitution Method, we have from eqn(1) that:
[tex]y=20-x\ldots\text{eqn}(3)[/tex]Putting eqn(3) into eqn(2), we get
[tex]\begin{gathered} 3x+11(20-x)=100 \\ 3x+220-11x=100 \end{gathered}[/tex]Collecting the like terms, we get
[tex]\begin{gathered} 3x-11x=100-220 \\ -8x=-120 \end{gathered}[/tex]Dividing both sides by -8, we get
[tex]x=\frac{-120}{-8}=15[/tex]So, the number of True/False questions in the assessment is 15.
To find x, we shall substitute 15 for x in eqn(3)
[tex]\begin{gathered} y=20-15 \\ y=5 \end{gathered}[/tex]Thus, the assessment has 5 multiple-choice questions.