Question

A closed-pipe resonator can produce sounds that have wavelengths that are four times the length of the pipe. Is this true or false?

Answer 1

The length of the pipe in terms of wavelength of the sound wave is,

$L=\frac{1}{4}\lambda$

Thus, the wavelength of the sound wave is,

$\lambda=4L$

where L is the length of the pipe.

$\lambda\text{ is the wavelength}$

Thus, the given statement is true.