GivenL
A) The hexagon having the perimeter 48 yd.
As hexagon is six sided polygon and its perimeter is given by,
[tex]\begin{gathered} P=6\times a \\ a\text{ is the measure of each side.} \\ 48=6\times a \\ a=8 \end{gathered}[/tex]
The area is calculated with the formula,
[tex]\begin{gathered} A=6\times\frac{\sqrt[]{3}}{4}\times a^2 \\ A=6\times\frac{\sqrt[]{3}}{4}\times8^2 \\ A=166.3yd^2 \end{gathered}[/tex]
B) the side length of pentagon is 6 ft . its area is calculated as,
[tex]\begin{gathered} A=\frac{1}{4}\sqrt[]{5(5+2\sqrt[]{5})}s^2 \\ A=\frac{1}{4}\sqrt[]{5(5+2\sqrt[]{5})}(6)^2 \\ =61.9ft^2 \end{gathered}[/tex]
