From the graph given,
The following points can be picked
Where x = 0, y = -5, i.e
[tex](x_1,y_1)\Rightarrow(0,-5)[/tex]
Where x = 2, y = 3, i.e
[tex](x_2,y_2)\Rightarrow(2,3)[/tex]
To find the equation of a straight line, the formula is
[tex]\frac{y-y_1}{x-x_1}=\frac{y_2-y_1}{x_2-x_1}[/tex]
Substitute the points into the formula above to find the equation of the graph
[tex]\begin{gathered} \frac{y-y_1}{x-x_1}=\frac{y_2-y_1}{x_2-x_1} \\ \frac{y-(-5)_{}}{x-0}=\frac{3-(-5)}{2-0} \\ \frac{y+5}{x}=\frac{3+5}{2} \\ \frac{y+5}{x}=\frac{8}{2} \\ \frac{y+5}{x}=\frac{4}{1} \\ \text{Crossmultiply} \\ 1(y+5)=4\times x \\ y+5=4x \\ y=4x-5 \end{gathered}[/tex]
The equation of the line is y = 4x -5 in the slope-intercept form
The general form of the equation of a straight line is
[tex]\begin{gathered} y=mx+b \\ \text{Where m is the slope and b is the y-intercept} \end{gathered}[/tex]
Relating both equations,
The slope, m, is 4 and the y-intercept, b, is -5
Hence, the answers are m = 4 and b = -5
[tex]\begin{gathered} m=4\text{ } \\ b=-5 \end{gathered}[/tex]
