[tex]\begin{gathered} 2\cdot\frac{1}{4}-1\cdot\frac{1}{2}-5\cdot\frac{1}{3} \\ 2\cdot\frac{1}{4}=\frac{9}{4} \\ 1\cdot\frac{1}{2}=\frac{3}{2} \\ 5\cdot\frac{1}{3}=\frac{16}{3} \\ \frac{9}{4}-\frac{3}{2}-\frac{16}{3}=-\frac{55}{12}=-4\cdot\frac{7}{12} \end{gathered}[/tex]
