[tex]x\approx437.3[/tex]
1) In this problem, we can find the leg by first finding the interior upper angle of that triangle.
2) Note that we can sketch this out and find the missing angle:
We can see that that upper angle is complementary.
So now, let's use a trig ratio so that we can find the opposite leg to angle 61º:
[tex]\begin{gathered} \sin (61^{\circ})=\frac{x}{500^{\square}} \\ x=500\cdot\sin (61^{\circ}) \\ x\approx437.3 \end{gathered}[/tex]
Thus this is the answer
