Question

given that two cards are dealt without replacement, what is the probability of the second card being an ace, given that the first card dealt was also an ace

Answer 1

Given:

The two cards are drawn without replacement from a deck of 52 cards.

So, total cards=52.

So the probability is given by,

$P=\frac{desired\text{ outcomes}}{\text{total outcomes}}$

The number Aces are 4 .

After picking first card there will be left 51 card in a deck.

Out of 4 ace card number of cards remains are 3.

The probability is given by,

$P=\frac{3}{51}$

So, the probability that second card is being an ace is P= 3/51 that is P=0.059.