Respuesta :

[tex]\frac{5+\sqrt{3}}{2-\sqrt{3}}[/tex]

multiply by the conjugate of the denominator

[tex]\frac{5+\sqrt{3}}{2-\sqrt{3}}\times\frac{2+\sqrt{3}}{2+\sqrt{3}}[/tex]

using the rule:

[tex](a+b)(a-b)=a^2-b^2[/tex]

then,

[tex]\frac{5+\sqrt{3}}{2-\sqrt{3}}\times\frac{2+\sqrt{3}}{2+\sqrt{3}}=\frac{(5+\sqrt{3})(2+\sqrt{3})}{2^2-(\sqrt{3})^2}[/tex]

simplify

[tex]\begin{gathered} \frac{10+5\sqrt{3}+2\sqrt{3}+(\sqrt{3})^2}{4-3} \\ \frac{10+5\sqrt{3}+2\sqrt{3}+3}{1} \\ 13+7\sqrt{3} \end{gathered}[/tex]

Answer:

After rationalizing the denominator the simplified expression is:

[tex]13+7\sqrt{3}[/tex]

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